He ( ) has one electron

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Atomic, Molecular & Optical Physics · One-electron atoms and the origins of atomic structure

Deriving the Spectrum, Ch Fine structure and the Lamb shift

Problem

He+^+ (Z=2Z=2) has one electron, so its 1S1S and 2S2S levels follow the same fine-structure formula as hydrogen's. Ignore the difference between its reduced mass and hydrogen's, take En=−Z2hcRH/n2E_n=-Z^2hcR_{\rm H}/n^2 with cRH=3.28805×106 GHzcR_{\rm H}=3.28805\times10^6\,\mathrm{GHz}, and take α=1/137.036\alpha=1/137.036. ((a)) Using the shift of an ss level, En22mc2(3−4n)\frac{E_n^2}{2mc^2}(3-4n), and En/mc2=−(Zα)2/2n2E_n/mc^2=-(Z\alpha)^2/2n^2, find how far fine structure moves the 1S1S and 2S2S levels of He+^+, in GHz. ((b)) Hence find how much fine structure widens the 1S1S-2S2S interval, and compare with the 30.1 GHz30.1\,\mathrm{GHz} by which it widens hydrogen's. ((c)) A non-relativistic treatment was expected to miss a fraction of order (Zα)2(Z\alpha)^2 of this interval, 34Z2cRH\tfrac34Z^2cR_{\rm H}. What fraction of that scale does the fine-structure widening actually reach?

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