Four excited levels of helium lie

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Atomic, Molecular & Optical Physics · Many-electron atoms and the periodic table

Deriving the Spectrum, Ch Helium: exchange and the variational method

Problem

Four excited levels of helium lie, above the 11S1^1S ground state, at 23S2^3S: 19.820 eV19.820\,\mathrm{eV}, 21S2^1S: 20.616 eV20.616\,\mathrm{eV}, 23P2^3P: 20.964 eV20.964\,\mathrm{eV} and 21P2^1P: 21.218 eV21.218\,\mathrm{eV}. Use two rules from the chapter: light cannot change the total spin, and a single photon cannot connect two states that both have zero orbital angular momentum. Take hc=1239.84 eV nmhc = 1239.84\,\mathrm{eV\,nm}. ((a)) List the one-photon decays open to 21P2^1P and give the wavelength of each. ((b)) Show that neither 23S2^3S nor 21S2^1S has any allowed one-photon decay, naming the rule that blocks each route. ((c)) A weak line from 23P12^3P_1 to the ground state is observed. Find its wavelength and say why the chapter's Hamiltonian cannot produce it.

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