The helium-like ion has nuclear charge and two electrons.

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Atomic, Molecular & Optical Physics · Many-electron atoms and the periodic table

Deriving the Spectrum, Ch Helium: exchange and the variational method

Problem

The helium-like ion Ne8+\mathrm{Ne}^{8+} has nuclear charge Z=10Z = 10 and two electrons. ((a)) Using the hydrogenic one-electron energy formula En=−Z22n2EhE_n = -\dfrac{Z^2}{2n^2}E_{\rm h} (Chapter 1), find the independent-electron ground-state energy E0E_0 of the 1s21s^2 configuration. Add the first-order repulsion ⟨1/r12⟩1s2=58Z Eh\langle 1/r_{12}\rangle_{1s^2} = \tfrac58 Z\,E_{\rm h} to obtain E1E_1, and use the one-electron energy of the remaining ion Ne9+\mathrm{Ne}^{9+} to find the first ionisation energy that E1E_1 predicts. Give all energies in eV, with Eh=27.211 eVE_{\rm h} = 27.211\,\mathrm{eV}. ((b)) Two electrons each carry spin 12\tfrac12. Using the rule for combining two angular momenta into a total (the same rule used in Chapter 2 to combine L⃗\vec L and S⃗\vec S into J⃗\vec J), list the possible values of the total spin quantum number SS for this pair, and for each value evaluate s⃗1⋅s⃗2=ℏ22[S(S+1)−32]\vec s_1\cdot\vec s_2 = \tfrac{\hbar^2}{2}\left[S(S+1)-\tfrac32\right]. For the 1s2s1s2s configuration of Ne8+\mathrm{Ne}^{8+}, unscreened hydrogenic orbitals give J1s2s=1781Z EhJ_{1s2s} = \tfrac{17}{81}Z\,E_{\rm h} and K1s2s=16729Z EhK_{1s2s} = \tfrac{16}{729}Z\,E_{\rm h}. Using the effective form E=Ea+Eb+Jab−12Kab(1+4s⃗1⋅s⃗2/ℏ2)E = E_a+E_b+J_{ab}-\tfrac12K_{ab}(1+4\vec s_1\cdot\vec s_2/\hbar^2), state which value of SS gives the lower energy and give the unscreened singlet-triplet splitting 2K1s2s2K_{1s2s} in eV.

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