Let and be two orthonormal one-electron orbitals ( ) with one-electron energies ,

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · Identical particles and many-particle quantum mechanics · Identical particles and many-particle quantum mechanics

Deriving the Spectrum, Ch Helium: exchange and the variational method

Problem

Let uau_a and ubu_b be two orthonormal one-electron orbitals (a≠ba\ne b) with one-electron energies EaE_a, EbE_b, and let ϕ±(1,2)=12[ua(1)ub(2)±ub(1)ua(2)]\phi_\pm(1,2) = \frac{1}{\sqrt2}\left[u_a(1)u_b(2) \pm u_b(1)u_a(2)\right] be the normalised symmetric (++) and antisymmetric (−-) two-electron spatial states. Define the direct integral Jab=∫∣ua(1)∣2∣ub(2)∣2 1r12 d3r1 d3r2J_{ab} = \displaystyle\int |u_a(1)|^2|u_b(2)|^2\,\frac{1}{r_{12}}\,d^3r_1\,d^3r_2 and the exchange integral Kab=∫ua∗(1)ub∗(2) 1r12 ub(1)ua(2) d3r1 d3r2K_{ab} = \displaystyle\int u_a^*(1)u_b^*(2)\,\frac{1}{r_{12}}\,u_b(1)u_a(2)\,d^3r_1\,d^3r_2. (a) Expand ⟨ϕ±∣1/r12∣ϕ±⟩\langle\phi_\pm|1/r_{12}|\phi_\pm\rangle in terms of the four two-electron integrals that appear, and show that two of them equal JabJ_{ab} and two equal KabK_{ab}. (b) Hence derive ⟨ϕ±∣1/r12∣ϕ±⟩=Jab±Kab\langle\phi_\pm|1/r_{12}|\phi_\pm\rangle = J_{ab}\pm K_{ab}, and so E±=Ea+Eb+Jab±KabE_\pm = E_a+E_b+J_{ab}\pm K_{ab} for the full two-electron energy (kinetic plus nuclear attraction plus repulsion).

Related theory

Browse the problem library