Sodium's principal-series levels lie

PHYSICS · Subjective · Fermi University Physics · Atomic, Molecular & Optical Physics · Many-electron atoms and the periodic table · Many-electron atoms and the periodic table

Deriving the Spectrum, Ch The central field and the periodic table

Problem

Sodium's principal-series levels lie, above the ground state, at 30 270.7 cm−130\,270.7\,\mathrm{cm^{-1}} (4p4p), 35 042.0 cm−135\,042.0\,\mathrm{cm^{-1}} (5p5p) and 37 297.2 cm−137\,297.2\,\mathrm{cm^{-1}} (6p6p). Fitting the 5p5p and 6p6p levels with a constant defect puts the limit 8 cm−18\,\mathrm{cm^{-1}} above the measured ionisation energy, 41 449.45 cm−141\,449.45\,\mathrm{cm^{-1}}. Take RNa=109 734.7 cm−1R_{\rm Na} = 109\,734.7\,\mathrm{cm^{-1}}, and let the defect drift as Ritz proposed, δp(n)=δ0+δ2/(n−δ0)2\delta_p(n) = \delta_0 + \delta_2/(n-\delta_0)^2. (a) Write the three equations that fix the limit LL, δ0\delta_0 and δ2\delta_2 from the three levels. (b) Solve them, and compare LL with the measured ionisation energy. (c) Use the fit to predict δp\delta_p for 3p3p, a level not used in the fit, and compare it with the value 0.8830.883 that sodium's 3p3p energy gives.

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