The Thomas-Fermi energy is the leading term of an expansion for large

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Atomic, Molecular & Optical Physics · Many-electron atoms and the periodic table

Deriving the Spectrum, Ch Self-consistent fields and correlation

Problem

The Thomas-Fermi energy ETF=−0.7687 Z7/3 EhE_{\rm TF}=-0.7687\,Z^{7/3}\,E_{\rm h} is the leading term of an expansion for large ZZ, and the terms after it are smaller by powers of Z−1/3Z^{-1/3}. Non-relativistic Hartree-Fock gives −128.547 Eh-128.547\,E_{\rm h} for neon (Z=10Z=10) and −21 866.8 Eh-21\,866.8\,E_{\rm h} for radon (Z=86Z=86). ((a)) For each atom find the gap Δ=EHF−ETF\Delta=E_{\rm HF}-E_{\rm TF} and the fractional error Δ/∣EHF∣\Delta/|E_{\rm HF}|. Show that if Δ\Delta grows as Z2Z^2, the fractional error falls roughly as Z−1/3Z^{-1/3}, and test this on the two atoms. ((b)) Assume Δ=cZ2\Delta=cZ^2. Find cc separately from neon and from radon, and say what their disagreement tells you. ((c)) Now assume Δ=cZ2−dZ5/3\Delta=cZ^2-dZ^{5/3}, one more power of Z−1/3Z^{-1/3}. Solve the two atoms' equations together for cc and dd, and compare with c=12c=\tfrac12 (Scott, 1952) and d=0.2699d=0.2699 (Schwinger, 1981), both derived from the theory itself. ((d)) The innermost electrons see nearly the bare potential −Z/r-Z/r, with hydrogen-like levels −Z2/2n2-Z^2/2n^2 holding 2n22n^2 electrons each. Fill the lowest NN shells exactly, then count the same electrons as a continuum in nn, as a local Fermi-gas model does, and show that the continuum count puts them lower in energy by Z2/2 EhZ^2/2\,E_{\rm h} for large NN. Explain why this makes the first correction positive and of order Z2Z^2.

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