Atomic germanium has ground configuration

PHYSICS · Multi-part · Fermi University Physics · Atomic, Molecular & Optical Physics · Many-electron atoms and the periodic table · Many-electron atoms and the periodic table

Deriving the Spectrum, Ch Many-electron terms, levels and Hund's rules

Problem

Atomic germanium has ground configuration 4p24p^2, in the same column as carbon and silicon, giving terms 3P^3P, 1D^1D, 1S^1S. The measured levels are 3P0=0 cm−1^3P_0=0\,\mathrm{cm^{-1}}, 3P1=557.13 cm−1^3P_1=557.13\,\mathrm{cm^{-1}}, 3P2=1409.96 cm−1^3P_2=1409.96\,\mathrm{cm^{-1}}, 1D2=7125.35 cm−1^1D_2=7125.35\,\mathrm{cm^{-1}}, 1S0=16367.19 cm−1^1S_0=16367.19\,\mathrm{cm^{-1}}. ((a)) Compute the (2J+1)(2J+1)-weighted centroid of the 3P^3P term. ((b)) Test the Slater-integral prediction E(1S)−E(1D)E(1D)−E(3P)=32\dfrac{E(^1S)-E(^1D)}{E(^1D)-E(^3P)}=\dfrac32 using the centroid. ((c)) Test the Lande interval rule on the 3P^3P term: compute the two intervals, their ratio, and the two ζLS\zeta_{LS} estimates. ((d)) Compare your results in (b) and (c) with carbon's measured 1.131.13 and 1.651.65, and explain why a good Slater-integral ratio does not guarantee a good interval rule.

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