Neutral has the ground configuration

PHYSICS · Multi-part · Fermi University Physics · Atomic, Molecular & Optical Physics · Molecular structure and spectra · Molecular structure and spectra

Deriving the Spectrum, Ch The Born-Oppenheimer separation and the chemical bond

Problem

Neutral O2\mathrm{O}_2 has the ground configuration …σg2p2 πu2p4 πg∗2\ldots\sigma_g2p^2\,\pi_u2p^4\,\pi_g^{*2}, giving a bond order of 22 and two unpaired electrons in the degenerate πg∗\pi_g^* level, so it is paramagnetic. ((a)) O2+\mathrm{O}_2^+ is formed by removing one electron from neutral O2\mathrm{O}_2. From which orbital is it removed, what bond order results, and is O2+\mathrm{O}_2^+ paramagnetic or diamagnetic? ((b)) O2−\mathrm{O}_2^- is formed by adding one electron to neutral O2\mathrm{O}_2. Into which orbital does it go, what bond order results, and is O2−\mathrm{O}_2^- paramagnetic or diamagnetic? ((c)) Rank O2−\mathrm{O}_2^-, O2\mathrm{O}_2 and O2+\mathrm{O}_2^+ in order of increasing bond strength.

Browse the problem library