A thin insulating ring of radius carries a charge spread uniformly around it

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Electrostatic fields and potential · Electrostatic fields and potential

Electricity, Magnetism and Electromagnetism, Ch Electrostatic potential, potential energy and the energy of the field

Problem

A thin insulating ring of radius a=0.12 ma = 0.12\ \mathrm{m} carries a charge Q=+4.0 nCQ = +4.0\ \mathrm{nC} spread uniformly around it. The ring lies in the xyxy-plane with its centre at the origin, so its axis is the zz-axis. All the charge is at rest and V=0V = 0 at infinity. Take PP to be the point on the axis at z=0.16 mz = 0.16\ \mathrm{m}. ((a)) Every element of the ring is the same distance from PP. Use this to write the potential V(z)V(z) at a general axial point and evaluate it at PP. ((b)) By differentiating your V(z)V(z), find the field component EzE_z at PP and state its direction. (On the axis Ex=Ey=0E_x = E_y = 0 by symmetry, so this is the whole field there.) ((c)) Find the electric field energy density at PP, and hence the field energy stored in a cube of side 1.0 mm1.0\ \mathrm{mm} centred on PP, over which the field may be treated as uniform.

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