A point charge is held fixed at the origin in vacuum

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Electrostatic fields and potential · Electrostatic fields and potential

Electricity, Magnetism and Electromagnetism, Ch Electrostatic potential, potential energy and the energy of the field

Problem

A point charge Q=4.0 nCQ = 4.0\,\mathrm{nC} is held fixed at the origin in vacuum. A small test charge q0=2.0 nCq_0 = 2.0\,\mathrm{nC} is carried slowly round a closed path that lies in a plane through QQ, so that kinetic energy may be ignored and the only work is that of the electrostatic force. The path has four legs, traversed in this order. Leg 1 runs straight, radially outward from r=0.10 mr = 0.10\,\mathrm{m} to r=0.30 mr = 0.30\,\mathrm{m} along one ray from QQ; leg 2 is a quarter circle of radius 0.30 m0.30\,\mathrm{m} centred on QQ; leg 3 runs straight, radially inward from r=0.30 mr = 0.30\,\mathrm{m} to r=0.10 mr = 0.10\,\mathrm{m}; leg 4 is a quarter circle of radius 0.10 m0.10\,\mathrm{m} centred on QQ, back to the start. Take k=1/4πε0=8.99×109 N m2 C−2k = 1/4\pi\varepsilon_0 = 8.99\times10^{9}\,\mathrm{N\,m^2\,C^{-2}}. ((a)) Starting from the line integral of the force in short straight steps, derive an expression for the work done by the electrostatic force on q0q_0 along a radial leg running from r1r_1 to r2r_2, and evaluate it for leg 1. ((b)) Show that legs 2 and 4 do no work, and hence give the total work done by the field round the whole closed path. ((c)) A uniformly charged spherical shell of radius R=5.0 cmR = 5.0\,\mathrm{cm} carries charge Q=4.0 nCQ = 4.0\,\mathrm{nC} spread uniformly over its surface and held at rest. Its field is zero inside and equal to Q/4πε0r2Q/4\pi\varepsilon_0 r^{2} radially outward at distance r≥Rr \ge R from the centre. Using the energy density u=12ε0E2u = \tfrac12\varepsilon_0E^2 and spherical layers of volume 4πr2 dr4\pi r^2\,dr, derive the total field energy of the shell and evaluate it.

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