A very long straight line of charge

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Electrostatic fields and potential · Electrostatic fields and potential

Electricity, Magnetism and Electromagnetism, Ch Electrostatic potential, potential energy and the energy of the field

Problem

A very long straight line of charge, treated as infinite and held at rest in vacuum, carries a uniform line charge density λ=2.5×10−8 C m−1\lambda = 2.5\times10^{-8}\,\mathrm{C\,m^{-1}}. Its field at perpendicular distance ss from the line is E=λ/2πε0sE = \lambda/2\pi\varepsilon_0 s, directed radially away from the line. Take ε0=8.854×10−12 F m−1\varepsilon_0 = 8.854\times10^{-12}\,\mathrm{F\,m^{-1}} and k=8.99×109 N m2 C−2k = 8.99\times10^{9}\,\mathrm{N\,m^2\,C^{-2}}. A closed path lies in a plane perpendicular to the line and is traversed in this order: outward along a straight radial leg from s=2.0 cms = 2.0\,\mathrm{cm} to s=8.0 cms = 8.0\,\mathrm{cm}; then a quarter circle of radius 8.0 cm8.0\,\mathrm{cm} centred on the line; then inward along a straight radial leg back to s=2.0 cms = 2.0\,\mathrm{cm}; then a quarter circle of radius 2.0 cm2.0\,\mathrm{cm} back to the start. ((a)) Derive an expression for ∫E⋅dl\int\mathbf{E}\cdot d\mathbf{l} along a radial leg from s1s_1 to s2s_2 and evaluate it for the outward leg, in volts. ((b)) Hence obtain ∮E⋅dl\oint\mathbf{E}\cdot d\mathbf{l} round the whole closed path. ((c)) Two concentric uniformly charged spherical shells are held at rest: the inner, of radius a=2.0 cma = 2.0\,\mathrm{cm}, carries +3.0 nC+3.0\,\mathrm{nC}, and the outer, of radius b=6.0 cmb = 6.0\,\mathrm{cm}, carries −3.0 nC-3.0\,\mathrm{nC}. The field is zero for r<ar < a and for r>br > b, and equals Q/4πε0r2Q/4\pi\varepsilon_0 r^2 radially outward for a<r<ba < r < b, with Q=3.0 nCQ = 3.0\,\mathrm{nC}. Using u=12ε0E2u = \tfrac12\varepsilon_0E^2 and layers 4πr2 dr4\pi r^2\,dr, derive the total field energy of this pair of shells and evaluate it.

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