Two long conductors share the axis: an inner wire of radius and an outer conducting…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Electricity, Magnetism & Electromagnetism · Vector calculus and field geometry

Electricity, Magnetism and Electromagnetism, Ch Divergence, curl and the local form of the field laws

Problem

Two long conductors share the zz axis: an inner wire of radius a=1.0 mma = 1.0\ \mathrm{mm} and an outer conducting cylinder whose inner surface is at radius b=4.0 mmb = 4.0\ \mathrm{mm}; the gap a<s<ba < s < b is vacuum, where s=x2+y2s = \sqrt{x^2+y^2}. The inner wire carries a steady current I=4.0 AI = 4.0\ \mathrm{A} along +z^+\hat{\mathbf{z}} and a uniform line charge λ=+2.5×10−9 C m−1\lambda = +2.5\times10^{-9}\ \mathrm{C\,m^{-1}}; the outer cylinder carries 4.0 A4.0\ \mathrm{A} back along −z^-\hat{\mathbf{z}} and −λ-\lambda per unit length. Everything is steady, so the fields are static. Treat the two conductors as infinitely long. In the gap the fields are E=λ2πε0 x x^+y y^x2+y2,B=μ0I2π −y x^+x y^x2+y2.\mathbf{E} = \frac{\lambda}{2\pi\varepsilon_0}\,\frac{x\,\hat{\mathbf{x}} + y\,\hat{\mathbf{y}}}{x^2+y^2},\qquad \mathbf{B} = \frac{\mu_0 I}{2\pi}\,\frac{-y\,\hat{\mathbf{x}} + x\,\hat{\mathbf{y}}}{x^2+y^2}. ((a)) Name the integral law, and the surface or loop, from which each of these two fields was obtained in Chapters 2 and 8, and give ∣E∣|\mathbf{E}| and ∣B∣|\mathbf{B}| at s=2.5 mms = 2.5\ \mathrm{mm}. ((b)) Compute ∇⋅E\nabla\cdot\mathbf{E} in the gap. What charge density does Gauss's law at a point therefore give there, and is that what you expect? ((c)) Compute ∇×B\nabla\times\mathbf{B} in the gap. What current density does the local form of Ampère's law give there? The circulation of B\mathbf{B} round a circle of radius 2.5 mm2.5\ \mathrm{mm} in the gap is μ0I≠0\mu_0 I \ne 0: explain, using Stokes's theorem, why this does not contradict your result. ((d)) Show that ∇×E=0\nabla\times\mathbf{E} = \mathbf{0} in the gap.

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