A coil has self-inductance and a winding of resistance

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Electric current and circuits · Electromagnetic induction and alternating-current circuits

Electricity, Magnetism and Electromagnetism, Ch Self and mutual inductance and magnetic field energy

Problem

A coil has self-inductance L=0.25 HL = 0.25\ \mathrm{H} and a winding of resistance R=3.0 ΩR = 3.0\ \Omega. Starting from zero current, a supply with an adjustable rheostat is used to raise the current in the coil at the uniform rate 20 A s−120\ \mathrm{A\,s^{-1}}, so that after 0.20 s0.20\ \mathrm{s} the current is 4.0 A4.0\ \mathrm{A}. Assume LL and RR are constant and that no energy leaves the coil except as Joule heat in its own winding. A student says: "The supply delivered 12LI2\tfrac12 LI^2 in total, because that is the energy the coil ends up with." ((a)) Find the energy stored in the coil's magnetic field at the end of the 0.20 s0.20\ \mathrm{s}. ((b)) Find the Joule heat produced in the winding during the same 0.20 s0.20\ \mathrm{s}. ((c)) Hence find the total electrical energy the supply delivered to the coil, and say where the quoted claim went wrong.

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