A battery-powered temperature logger needs a low-pass filter ahead of its…

PHYSICS · Multi-part · Fermi University Physics · Electronics, Instrumentation & Communication · Feedback, operational amplifiers and analogue signal processing · Feedback, operational amplifiers and analogue signal processing

Electronics for Measurement, Ch Active filters, oscillators and timers

Problem

A battery-powered temperature logger needs a low-pass filter ahead of its analogue-to-digital converter. An engineer designs an equal-component Sallen-Key section for a 500 Hz500\,\mathrm{Hz} corner and Q=0.707Q = 0.707 (Butterworth damping), using the nearest E12 preferred values R=15 kΩR = 15\,\mathrm{k}\Omega for both frequency-setting resistors and C=22 nFC = 22\,\mathrm{nF} for both frequency-setting capacitors, with passband gain K=1.586K = 1.586. The op-amp used has an input voltage-noise density en=8 nV/Hze_n = 8\,\mathrm{nV}/\sqrt{\mathrm{Hz}}. The noise-equivalent bandwidth of a Q=0.707Q = 0.707 second-order section is 1.11 f01.11\,f_0. Room temperature is 290 K290\,\mathrm{K}. ((a)) Find the realised corner frequency f0f_0. ((b)) Find the rms output noise voltage, taking the two 15 kΩ15\,\mathrm{k}\Omega resistors as the only thermal-noise source in series with the amplifier's own noise, referred through the passband gain KK (ignore the feedback resistors' own noise). ((c)) A downstream stage must reject an interferer at five times the passband corner by at least 30 dB30\,\mathrm{dB}. Using the Butterworth magnitude ∣H∣=1/1+(f/f0)2n|H| = 1/\sqrt{1+(f/f_0)^{2n}} for an nnth-order Butterworth low-pass with its corner at f0f_0, find the minimum order nn.

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