Two calibration constants of a detector have measured standard deviations mm and mm

PHYSICS · Multi-part · Fermi University Physics · Scientific Practice & Experimental Methods · Mathematical Methods for Physics · Uncertainty in measurement

Error, Chance and the Machine, Ch Linear systems, least squares and the singular value decomposition

Problem

Two calibration constants of a detector have measured standard deviations σ1=4\sigma_1 = 4 mm and σ2=5\sigma_2 = 5 mm, with covariance matrix C=(σ12ρ σ1σ2ρ σ1σ2σ22).\mathsf{C} = \begin{pmatrix}\sigma_1^2 & \rho\,\sigma_1\sigma_2\\ \rho\,\sigma_1\sigma_2 & \sigma_2^2\end{pmatrix}. ((a)) For a correlation coefficient ρ=0.6\rho = 0.6, construct the upper-triangular Cholesky factor R\mathsf{R} with C=RTR\mathsf{C} = \mathsf{R}^{\rm T}\mathsf{R}, giving r11r_{11}, r12r_{12} and r22r_{22}. ((b)) Repeat the calculation for ρ=1.3\rho = 1.3 and show that the factorisation fails; give the value of the pivot at which it fails and explain what this means physically.

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