The general linear isotropic relation between the viscous stress and the velocity…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Fluids & Continuum Physics · Solid continuum mechanics and complex fluids

Fluid Dynamics, Ch The stress tensor completed: constitutive law and fluid properties

Problem

The general linear isotropic relation between the viscous stress and the velocity gradient is τij=Aijkl ∂uk/∂xl\tau_{ij} = A_{ijkl}\,\partial u_k/\partial x_l with Aijkl=a δijδkl+b δikδjl+c δilδjkA_{ijkl} = a\,\delta_{ij}\delta_{kl} + b\,\delta_{ik}\delta_{jl} + c\,\delta_{il}\delta_{jk}, and ∂uk/∂xl=ekl+Ωkl\partial u_k/\partial x_l = e_{kl}+\Omega_{kl} splits into the symmetric rate of strain ekle_{kl} and the antisymmetric part Ωkl\Omega_{kl}. ((a)) Show that the bb and cc terms of τij\tau_{ij} depend on Ωkl\Omega_{kl} only through the combination b−cb-c, and use the requirement that rigid rotation carries no viscous stress to show b=c≡μb=c\equiv\mu. ((b)) With b=c=μb=c=\mu and μb≡a+23μ\mu_b \equiv a+\tfrac23\mu, the stress reduces to τij=2μ(eij−13ekkδij)+μbekkδij\tau_{ij} = 2\mu\big(e_{ij}-\tfrac13 e_{kk}\delta_{ij}\big)+\mu_b e_{kk}\delta_{ij}. Show that the dissipation function Φ=τijeij\Phi=\tau_{ij}e_{ij} reduces to a sum of two non-negative squared terms, and deduce the sign that μ\mu and μb\mu_b must each have.

Browse the problem library