Change to the frame in which the fluid is at rest far away and a sphere of radius…

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Kinematics, conservation laws and ideal flow · Kinematics, conservation laws and ideal flow

Fluid Dynamics, Ch Potential flow, conformal mapping and the finite wing

Problem

Change to the frame in which the fluid is at rest far away and a sphere of radius aa moves through it at speed UU. The velocity potential of this flow is the dipole ϕ=−Ua3cos⁡θ2r2\phi = -\dfrac{Ua^3\cos\theta}{2r^2}, chosen so that ur(a,θ)=Ucos⁡θu_r(a,\theta) = U\cos\theta matches the normal velocity of the moving sphere's surface. ((a)) Find ur=∂ϕ/∂ru_r = \partial\phi/\partial r and uθ=r−1∂ϕ/∂θu_\theta = r^{-1}\partial\phi/\partial\theta, and hence show that the kinetic energy of the fluid, 12ρ∫r≥a(ur2+uθ2) dV\tfrac12\rho\int_{r \ge a}(u_r^2+u_\theta^2)\,\mathrm{d}V with dV=2πr2sin⁡θ dr dθ\mathrm{d}V = 2\pi r^2\sin\theta\,\mathrm{d}r\,\mathrm{d}\theta, equals 12maU2\tfrac12m_aU^2 with ma=12ρ⋅43πa3m_a = \tfrac12\rho\cdot\tfrac43\pi a^3, the added mass. ((b)) A hollow plastic ball of radius a=2.0 cma = 2.0\,\mathrm{cm} and uniform density 100 kg m−3100\,\mathrm{kg\,m^{-3}} is released from rest, fully submerged, in still water (ρ=998 kg m−3\rho = 998\,\mathrm{kg\,m^{-3}}). Using (mball+ma)dUdt=(ρwater−ρball)Vg(m_{\text{ball}}+m_a)\dfrac{\mathrm{d}U}{\mathrm{d}t} = (\rho_{\text{water}}-\rho_{\text{ball}})Vg at the instant of release, find its initial acceleration as a multiple of gg.

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