For flow over a flat plate at zero pressure gradient

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Fluids & Continuum Physics · Viscous flow and dynamical similarity

Fluid Dynamics, Ch The boundary layer: Prandtl's equations and the Blasius solution

Problem

For flow over a flat plate at zero pressure gradient, the momentum integral method uses an assumed velocity profile u/U=f(η)u/U=f(\eta), η=y/δ\eta=y/\delta, with f(0)=0f(0)=0, f(1)=1f(1)=1, f′(1)=0f'(1)=0. Suppose the quadratic profile f(η)=2η−η2f(\eta)=2\eta-\eta^2 is used instead of the linear profile (δ=3.46x/Rex\delta=3.46x/\sqrt{Re_x}, Cf=0.577/RexC_f=0.577/\sqrt{Re_x}) or the Pohlhausen cubic profile (δ=4.64x/Rex\delta=4.64x/\sqrt{Re_x}, Cf=0.646/RexC_f=0.646/\sqrt{Re_x}). ((a)) Using the quadratic profile, derive δ1\delta_1 and δ2\delta_2 in terms of δ\delta, then use the momentum integral equation to derive δ(x)=A x/Rex\delta(x)=A\,x/\sqrt{Re_x} and Cf(x)=B/RexC_f(x)=B/\sqrt{Re_x}, giving AA and BB. ((b)) State the percentage by which this CfC_f differs from the Blasius value 0.664/Rex0.664/\sqrt{Re_x}, and say whether the quadratic profile is more or less accurate than the linear and cubic profiles quoted above. ((c)) The wall relation μ ∂2u/∂y2∣y=0=dp/dx\mu\,\partial^2u/\partial y^2|_{y=0}=\mathrm{d}p/\mathrm{d}x must hold. Check whether the quadratic profile satisfies it for a flat plate (dp/dx=0\mathrm{d}p/\mathrm{d}x=0), and explain why none of the linear, quadratic or cubic profiles used here could represent a layer with an inflection point, of the kind an adverse pressure gradient produces.

Browse the problem library