In a deep water tank a slow upwelling is driven above a diffuser and spreads out…

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Kinematics, conservation laws and ideal flow · Kinematics, conservation laws and ideal flow

Fluids and Continuum Physics, Ch Kinematics of flow: fields, streamlines and the material derivative

Problem

In a deep water tank a slow upwelling is driven above a diffuser and spreads out beneath the free surface. Take zz upward from the free surface, so zz is negative in the water, and xx, yy horizontal. The steady field measured near the axis is u=Sx,v=Sy,w=−2Sz,S=0.15 s−1,u = Sx, \qquad v = Sy, \qquad w = -2Sz, \qquad S = 0.15\ \mathrm{s^{-1}}, with coordinates in metres. The water has uniform density ρ=1000 kg m−3\rho = 1000\ \mathrm{kg\,m^{-3}}, g=9.8 m s−2g = 9.8\ \mathrm{m\,s^{-2}}, the atmosphere above the surface is at 1.013×105 Pa1.013\times10^{5}\ \mathrm{Pa}, and the pressure may be treated as hydrostatic, p=patm−ρgzp = p_{\mathrm{atm}} - \rho g z (absolute). ((a)) Test the field for incompressibility. ((b)) Find the absolute pressure at the point PP: x=0.30 mx = 0.30\ \mathrm{m}, y=−0.20 my = -0.20\ \mathrm{m}, z=−0.80 mz = -0.80\ \mathrm{m}. ((c)) Find Dp/DtDp/Dt for the parcel at PP and say whether the pressure it carries rises or falls. ((d)) The sensor at PP hangs from a nylon line of length 5.0 m5.0\ \mathrm{m} and diameter 1.2 mm1.2\ \mathrm{mm} under a tension of 12 N12\ \mathrm{N}. The nylon is elastic with Young modulus 3.0 GPa3.0\ \mathrm{GPa} and the weight of the line itself is ignored. Find its extension.

Browse the problem library