A tall brick chimney of circular cross-section

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Kinematics, conservation laws and ideal flow · Kinematics, conservation laws and ideal flow

Fluids and Continuum Physics, Ch Potential flow, complex potentials and lift

Problem

A tall brick chimney of circular cross-section, radius a=0.60a = 0.60 m and vertical axis, stands in a horizontal wind of speed U=12U = 12 m s−1^{-1}. Take the air to be of uniform density ρ=1.2\rho = 1.2 kg m−3^{-3} and the flow in the horizontal plane through a point half way up the chimney to be steady, incompressible, inviscid and irrotational, with the stream along +x+x. All points considered lie at the same height, so the ρgz\rho g z term is the same everywhere. Far from the chimney the absolute pressure is p∞=1.013×105p_\infty = 1.013\times10^{5} Pa. The polar angle θ\theta is measured from the +x+x axis, so the stagnation points of the ideal flow lie at θ=0\theta = 0 and θ=180∘\theta = 180^{\circ} and the shoulders at θ=±90∘\theta = \pm 90^{\circ}. ((a)) Very close to the upstream stagnation point, take local coordinates xx, yy in metres centred on that point, with xx along the chimney surface and yy pointing upstream, away from the surface. There the flow is described by the velocity potential ϕ=12S(x2−y2)\phi = \tfrac12 S(x^{2} - y^{2}) with S=2U/a=40S = 2U/a = 40 s−1^{-1} and ϕ\phi in m2^{2} s−1^{-1}. Verify that ϕ\phi satisfies Laplace's equation, write down the velocity field, and find the flow speed at the point (x,y)=(0.020,0.030)(x, y) = (0.020, 0.030) m. ((b)) Find the absolute pressure on the surface of the chimney at the shoulder θ=90∘\theta = 90^{\circ}. ((c)) The chimney is fitted with a device that gives the flow round it a circulation Γ=−80\Gamma = -80 m2^{2} s−1^{-1} (that is, clockwise). Find the transverse force per unit length of chimney and say whether it acts along +y+y or −y-y.

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