Adult haemoglobin has and Hill coefficient

PHYSICS · Multi-part · Fermi University Physics · Biophysics & Medical Physics · Macromolecules, membranes and cell architecture · Macromolecules, membranes and cell architecture

Forces, Machines and Signals, Ch Cooperativity: zippers, melting and allosteric binding

Problem

Adult haemoglobin has p50adult=26 mmHgp_{50}^{\text{adult}} = 26\,\mathrm{mmHg} and Hill coefficient nH=2.8n_H = 2.8. Two points read off a foetal-blood binding curve are Y=0.142Y=0.142 at p=10 mmHgp=10\,\mathrm{mmHg} and Y=0.889Y=0.889 at p=40 mmHgp=40\,\mathrm{mmHg}. ((a)) Fit the Hill function to the two foetal points: plot ln⁡[Y/(1−Y)]\ln[Y/(1-Y)] against ln⁡p\ln p, and find the foetal Hill coefficient and p50foetalp_{50}^{\text{foetal}}. ((b)) Compute the fractional saturation YY of adult and of foetal haemoglobin at the placental oxygen partial pressure p=20 mmHgp=20\,\mathrm{mmHg}, using the Hill function Y=pnH/(p50nH+pnH)Y=p^{n_H}/(p_{50}^{n_H}+p^{n_H}) with the adult values and your fitted foetal values. ((c)) Repeat the calculation for both carriers treated as non-cooperative, independent sites of the same respective p50p_{50} values (i.e. nH=1n_H=1), at the same pressure p=20 mmHgp=20\,\mathrm{mmHg}. ((d)) Compare the saturation difference (foetal minus adult) in the cooperative case with that in the independent-site case, and explain briefly how the difference in p50p_{50} allows foetal blood to pick up oxygen released by maternal (adult) haemoglobin at the placenta.

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