Hill's force-velocity relation for a fully activated muscle (or for a single…
PHYSICS · Multi-part · Fermi University Physics · Biophysics & Medical Physics · Molecular machines, transport and bioenergetics · Molecular machines, transport and bioenergetics
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Problem
Hill's force-velocity relation for a fully activated muscle (or for a single actomyosin cross-bridge ensemble) can be writtenv(F)=F+ab(F0−F),where F0 is the isometric (zero-velocity) force, F is the load, and a (a force) and b (a velocity) are positive constants. This relation is an empirical fit to measurements, quoted here.
((a)) The mechanical power delivered against the load is P(F)=Fv(F). Find the load F∗ at which this power is largest, in terms of a and F0.
((b)) Find how F∗/F0 behaves as a/F0→0 and as a/F0→∞. In which limit does Hill's relation become a straight line from its top speed at zero load to zero speed at F0, and why does the power then peak at exactly half the isometric force?
((c)) A different muscle has an isometric force F0=150N and a Hill constant a=60N (so a/F0=0.40). Find, in newtons and as a fraction of F0, the load at which this muscle delivers its maximum mechanical power.