The Z-scheme of oxygenic photosynthesis is usually drawn as a ladder of redox…

PHYSICS · Multi-part · Fermi University Physics · Biophysics & Medical Physics · Molecular machines, transport and bioenergetics · Molecular machines, transport and bioenergetics

Forces, Machines and Signals, Ch Proton gradients, ATP synthesis and photosynthesis

Problem

The Z-scheme of oxygenic photosynthesis is usually drawn as a ladder of redox potentials: water is oxidised at E∘′(O2/H2O)=+0.82 VE^{\circ\prime}(\mathrm{O_2/H_2O}) = +0.82\,\mathrm{V}; absorption of a photon at photosystem II (680 nm680\,\mathrm{nm}) lifts an electron high enough to pass down an electron-transport chain to photosystem I; absorption of a second photon there, at 700 nm700\,\mathrm{nm}, lifts the electron again and delivers it finally to NADP+/NADPH\mathrm{NADP^+/NADPH} at E∘′=−0.32 VE^{\circ\prime} = -0.32\,\mathrm{V}. Measured quantum requirements show that, in practice, about 1010 photons in total (roughly 55 absorbed at each photosystem) are used for every O2\mathrm{O_2} released (four electrons transferred), rather than the theoretical minimum of 88. ((a)) Translate the description above into numbers: state, in eV\mathrm{eV}, the energy of one 680 nm680\,\mathrm{nm} photon, one 700 nm700\,\mathrm{nm} photon, and the free-energy span of the water-to-NADP+\mathrm{NADP^+} step that the two photons together must drive. ((b)) Using the measured quantum requirement of 1010 photons per O2\mathrm{O_2} (not the theoretical minimum), calculate the percentage of the total absorbed photon energy that ends up stored across that span, per O2\mathrm{O_2} released.

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