An unmyelinated invertebrate axon has radius

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Biophysics & Medical Physics · Bioelectricity, the senses and the physics of the body

Forces, Machines and Signals, Ch The nerve impulse

Problem

An unmyelinated invertebrate axon has radius a=90 μma = 90\,\mathrm{\mu m}, specific membrane resistance Rm=2000 Ω cm2R_m = 2000\,\Omega\,\mathrm{cm^2}, specific membrane capacitance Cm=1 μF cm−2C_m = 1\,\mathrm{\mu F\,cm^{-2}}, axial resistivity Ri=50 Ω cmR_i = 50\,\Omega\,\mathrm{cm}, and a sodium activation time τact=0.3 ms\tau_{\rm act} = 0.3\,\mathrm{ms} set by channel kinetics rather than geometry. ((a)) Starting from Kirchhoff's current law applied to a ladder of axial resistors and membrane resistor-capacitor pairs, derive the cable equation λ2V′′=τVt+V\lambda^2V''=\tau V_t+V and give λ=aRm/2Ri\lambda=\sqrt{aR_m/2R_i} and τ=RmCm\tau=R_mC_m in terms of the specific quantities RiR_i, RmR_m, CmC_m and aa. ((b)) Ahead of a wave of fixed shape moving at speed vv, V(x−vt)V(x-vt), the resting membrane must be charged towards threshold within the sodium activation time τact\tau_{\rm act}, much shorter than τ\tau. Treating the cable over that short time as a diffusion equation with D=λ2/τD=\lambda^2/\tau, show that v∼D/τact=λ/τ τact∝av\sim\sqrt{D/\tau_{\rm act}}=\lambda/\sqrt{\tau\,\tau_{\rm act}}\propto\sqrt a at fixed RiR_i, CmC_m, τact\tau_{\rm act}, and explain why RmR_m drops out. ((c)) Compute λ\lambda, τ\tau and the estimated conduction velocity of this axon. ((d)) A thicker axon of the same species, with the same RmR_m, RiR_i, CmC_m and τact\tau_{\rm act}, conducts at exactly twice this speed. Use the scaling law of part (b) to find its radius.

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