A mesenteric artery of radius carrying steady Poiseuille flow divides into two…

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Biophysics & Medical Physics · Viscous flow and dynamical similarity

Forces, Machines and Signals, Ch Bones, blood and body size

Problem

A mesenteric artery of radius r0r_0 carrying steady Poiseuille flow Q0Q_0 divides into two daughter vessels of radii r1r_1 and r2r_2 carrying flows Q1Q_1 and Q2Q_2, with Q0=Q1+Q2Q_0=Q_1+Q_2. Blood has viscosity η\eta, and the metabolic cost of maintaining a unit length of vessel filled with blood is bVb_V per unit cross-sectional area, both the same throughout the tree. The total cost per unit length of a vessel of radius rr carrying flow QQ is the sum of the pumping power per unit length (from Poiseuille's law) and the metabolic cost of its blood volume: C(r)=8ηQ2πr4+bVπr2.\mathcal{C}(r) = \frac{8\eta Q^2}{\pi r^4} + b_V\pi r^2. ((a)) Minimise C\mathcal{C} with respect to rr at fixed QQ and show that the optimum satisfies Q=kr3Q = k r^3 for a constant kk that is the same for every vessel in the tree. ((b)) Use conservation of flow at the branch together with the result of part (a) to derive Murray's law, r03=r13+r23r_0^3 = r_1^3+r_2^3. ((c)) The parent radius is r0=1.80 mmr_0 = 1.80\,\mathrm{mm} and one daughter has radius r1=1.50 mmr_1 = 1.50\,\mathrm{mm}. Find the radius r2r_2 of the other daughter. ((d)) Show, using Q=kr3Q=kr^3, that the Poiseuille wall shear stress τw=4ηQ/(πr3)\tau_{\rm w} = 4\eta Q/(\pi r^3) is the same in the parent and both daughters, and compute the ratio of the daughters' total cross-sectional area to the parent's cross-sectional area for this branch.

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