A current-mode boost converter steps up to with inductor

PHYSICS · Multi-part · Fermi University Physics · Electronics, Instrumentation & Communication · Semiconductor devices and analogue circuits · Feedback, operational amplifiers and analogue signal processing

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Problem

A current-mode boost converter steps 9 V9\,\mathrm{V} up to 24 V24\,\mathrm{V} with inductor L=22 μHL = 22\,\mu\mathrm{H}, delivering Io=0.5 AI_o = 0.5\,\mathrm{A}. Its compensated loop is designed so that near crossover T(s)≈(ωc/s)(1−s/ωz)T(s) \approx (\omega_c/s)(1-s/\omega_z), with ωc=2πfc\omega_c = 2\pi f_c set by the compensator at the nominal crossover fc=8 kHzf_c = 8\,\mathrm{kHz} and the right-half-plane zero at ωz=(1−D)2RL/L\omega_z = (1-D)^2 R_L/L, RL=Vo/IoR_L = V_o/I_o. Because the zero lifts ∣T(jωc)∣|T(j\omega_c)| slightly above one, estimate each phase margin at fcf_c. ((a)) Find the duty cycle DD and the zero frequency fzf_z at Io=0.5 AI_o = 0.5\,\mathrm{A}, and the resulting phase margin at fc=8 kHzf_c = 8\,\mathrm{kHz}. ((b)) Find the new zero frequency and phase margin if the load current doubles to Io=1.0 AI_o = 1.0\,\mathrm{A} (same fcf_c). ((c)) Using the Nyquist criterion for a non-minimum-phase loop with a single unity-gain crossing, show that the loop remains stable at both loads by evaluating the high-frequency limit of ∣T∣|T|.

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