In a crystal a small strain produces an electric polarisation

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Tensors and differential geometry · Tensors and differential geometry

Invariance, Ch Index notation and Cartesian tensors

Problem

In a crystal a small strain ejke_{jk} produces an electric polarisation P\mathbf P. The response is written provisionally as Pi=dijkejkP_i=d_{ijk}e_{jk}, with 2727 array entries dijkd_{ijk} in one set of axes; how many of them measurements can fix is part of the question. (Here dijkd_{ijk} couples polarisation to strain, not to stress as the tabulated dd coefficients usually do.) P\mathbf P is a vector and the strain is a symmetric rank-two tensor, ejk=ekje_{jk}=e_{kj}. The relation holds in every set of axes and for every strain the crystal can be given, but no experiment can apply a strain that is not symmetric. ((a)) Follow the quotient-theorem argument for rank two and show that Bijkejk′=0B_{ijk}e'_{jk}=0 for every symmetric ejk′e'_{jk}, where Bijk=dijk′−RilRjmRkndlmnB_{ijk}=d'_{ijk}-\mathsf R_{il}\mathsf R_{jm}\mathsf R_{kn}d_{lmn}. ((b)) The rank-two argument ended by taking the input along each axis in turn. Show by an example that here Bijkejk=0B_{ijk}e_{jk}=0 for every symmetric ejke_{jk} does not force Bijk=0B_{ijk}=0, and find exactly what it does force. ((c)) Conclude which combination of the dijkd_{ijk} obeys the rank-three tensor law, and how many independent coefficients the measurements can determine.

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