A rectangular plane lattice has primitive vectors and with and (lengths on a scale…

PHYSICS · Multi-part · Fermi University Physics · Condensed Matter, Materials & Soft Matter · Crystal structure, bonding and diffraction · Crystal structure, bonding and diffraction

Invariance, Ch Point groups and crystallographic symmetry

Problem

A rectangular plane lattice has primitive vectors a=(a,0)\mathbf a=(a,0) and b=(0,b)\mathbf b=(0,b) with a=4.00 cma=4.00\,\text{cm} and b=3.00 cmb=3.00\,\text{cm} (lengths on a scale drawing; only their ratio matters). A second net is built by adding one extra lattice point at the centre of every rectangle, at (a/2,b/2)(a/2,b/2) relative to each corner point. ((a)) Show that the vectors a1=(a/2,b/2)\mathbf a_1=(a/2,b/2) and a2=(a/2,−b/2)\mathbf a_2=(a/2,-b/2) generate every point of the centred net, corners and added centres alike, and find the area of the primitive cell they define. ((b)) Compute ∣a1∣|\mathbf a_1|, ∣a2∣|\mathbf a_2| and the angle between them for the given aa and bb, and show that this cell is a rhombus, not a rectangle. ((c)) Compare ∣a1∣,∣a2∣|\mathbf a_1|,|\mathbf a_2| with aa and bb to argue that the rhombus, not the original rectangle, is the true primitive cell of the centred net. State whether the centred net drawn here is the same plane lattice as a primitive rectangular net, and say what changes if instead a=ba=b.

Browse the problem library