Three identical LC circuits sit at the corners of an equilateral triangle and a…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Group theory and symmetry · Group theory and symmetry

Invariance, Ch Representations, Schur's lemma and characters

Problem

Three identical LC circuits sit at the corners of an equilateral triangle and a fourth sits at its centre, all coupled through their capacitors, with the whole arrangement carrying C3vC_{3v} symmetry (classes EE, 2C32C_3, 3σv3\sigma_v, so ∣G∣=6|G|=6). Take as coordinates the four capacitor charges, which the symmetry operations permute. The representation of C3vC_{3v} on the four charges has character χ=(4,1,2)\chi = (4, 1, 2) on these classes. The C3vC_{3v} character table is A1=(1,1,1)A_1 = (1,1,1), A2=(1,1,−1)A_2 = (1,1,-1), E=(2,−1,0)E = (2,-1,0) on classes (E,2C3,3σv)(E, 2C_3, 3\sigma_v). Someone decomposes χ\chi as follows: "The decomposition formula is ai=1∣G∣∑classesχ(g)χi(g)∗a_i = \frac{1}{|G|}\sum_{\text{classes}} \chi(g)\chi_i(g)^*. So aA1=16(4⋅1+1⋅1+2⋅1)=76a_{A_1} = \frac{1}{6}(4\cdot 1 + 1\cdot 1 + 2\cdot 1) = \frac{7}{6} aA2=16(4⋅1+1⋅1+2⋅(−1))=12a_{A_2} = \frac{1}{6}(4\cdot 1 + 1\cdot 1 + 2\cdot(-1)) = \frac{1}{2} aE=16(4⋅2+1⋅(−1)+2⋅0)=76a_E = \frac{1}{6}(4\cdot 2 + 1\cdot(-1) + 2\cdot 0) = \frac{7}{6} so χ\chi contains fractional amounts of each irreducible representation." ((a)) Confirm the character by counting the charges each operation leaves in place, and find the error in this working. ((b)) Give the correct decomposition of χ\chi into irreducible representations of C3vC_{3v}, and check that the dimensions add up to 44.

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