Carbon disulfide,

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Atomic, Molecular & Optical Physics · Molecular structure and spectra

Invariance, Ch Character tables at work: vibrations, selection rules and splitting

Problem

Carbon disulfide, CS2\mathrm{CS_2}, is a linear, centrosymmetric triatomic, S=C=S\mathrm{S{=}C{=}S}. As with CO2\mathrm{CO_2}, its full symmetry is treated in the finite subgroup D4hD_{4h}: for this molecule Γ3N=A1g+Eg+2A2u+2Eu\Gamma_{3N}=A_{1g}+E_g+2A_{2u}+2E_u, with basis functions z→A2uz\to A_{2u}, (x,y)→Eu(x,y)\to E_u, quadratics x2+y2, z2→A1gx^2+y^2,\,z^2\to A_{1g}, xy→B2gxy\to B_{2g}, x2−y2→B1gx^2-y^2\to B_{1g}, (xz,yz)→Eg(xz,yz)\to E_g. ((a)) Remove translations (A2u+EuA_{2u}+E_u) and rotations (EgE_g) from Γ3N\Gamma_{3N} to find Γvib\Gamma_{\rm vib}, and identify the symmetric stretch, the bend and the antisymmetric stretch. ((b)) Decompose the direct product A2u⊗EuA_{2u}\otimes E_u with the characters of the D4hD_{4h} table, and say whether it contains A1gA_{1g}. ((c)) Using the vanishing integral theorem and the quadratic functions listed, decide whether the antisymmetric stretch (A2uA_{2u}) is Raman active. ((d)) Say whether either stretch is active in both the infrared and the Raman spectrum, and name the principle that decides it.

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