A patient with a mean aortic flow speed of (Chapter 5) is scanned

PHYSICS · Multi-part · Fermi University Physics · Biophysics & Medical Physics · Radiation physics and diagnostic imaging · Nuclear medicine, dosimetry and radiotherapy

Life at Thermal Energy, Ch Echoes, precession and the therapeutic beam

Problem

A patient with a mean aortic flow speed of 0.17 m s−10.17\,\mathrm{m\,s^{-1}} (Chapter 5) is scanned, treated and modelled in three ways. Take cs=1540 m s−1c_s = 1540\,\mathrm{m\,s^{-1}}, kBT/e=26.7 mVk_BT/e = 26.7\,\mathrm{mV} at body temperature (the voltage scale of a Nernst potential, Chapter 4), and the nuclear spin level gap at 1.5 T1.5\,\mathrm{T} as ΔE/kBT=9.9×10−6\Delta E/k_BT = 9.9\times10^{-6}. ((a)) An ultrasound probe at f=4 MHzf = 4\,\mathrm{MHz} is held at θ=45∘\theta = 45^\circ to the aorta. Calculate the Doppler shift Δf\Delta f. ((b)) The potassium Nernst potential of this patient's cells has magnitude ∣EK∣=90 mV|E_{\rm K}| = 90\,\mathrm{mV}. At that equilibrium, the Boltzmann factor e−ze∣EK∣/kBTe^{-ze|E_{\rm K}|/k_BT} for an ion of valence z=1z=1 (Chapter 4) is the ratio of the smaller potassium concentration to the larger. Compute this factor, and the Boltzmann factor e−ΔE/kBTe^{-\Delta E/k_BT} for a proton spin at 1.5 T1.5\,\mathrm{T}. By what factor do the two exponents ze∣EK∣/kBTze|E_{\rm K}|/k_BT and ΔE/kBT\Delta E/k_BT differ? ((c)) The patient's tumour (αLQ=0.3 Gy−1\alpha_{\rm LQ} = 0.3\,\mathrm{Gy^{-1}}, βLQ=0.03 Gy−2\beta_{\rm LQ} = 0.03\,\mathrm{Gy^{-2}}) and late-responding tissue (αLQ=0.15 Gy−1\alpha_{\rm LQ} = 0.15\,\mathrm{Gy^{-1}}, βLQ=0.05 Gy−2\beta_{\rm LQ} = 0.05\,\mathrm{Gy^{-2}}) are treated with 2020 fractions of 2.5 Gy2.5\,\mathrm{Gy}. Using ln⁡S=−(αLQD+βLQD2)\ln\mathcal{S} = -(\alpha_{\rm LQ}\mathcal{D} + \beta_{\rm LQ}\mathcal{D}^2) per fraction, calculate the surviving fraction S\mathcal{S} of each after the full course.

Browse the problem library