A load carries voltage and current

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Electricity, Magnetism & Electromagnetism · Foundations of mathematical language

Mathematical Methods for Physics, Ch Complex numbers, the complex exponential and phasors

Problem

A load carries voltage V(t)=8.0cos⁡(ωt) VV(t) = 8.0\cos(\omega t)\,\mathrm{V} and current I(t)=3.0cos⁡(ωt−π/4) AI(t) = 3.0\cos(\omega t - \pi/4)\,\mathrm{A}. With the phasor convention Acos⁡(ωt+ϕ)=Re[A~e−iωt]A\cos(\omega t+\phi)=\mathrm{Re}[\tilde A e^{-i\omega t}] and A~=Ae−iϕ\tilde A = Ae^{-i\phi}, the complex amplitudes are V~=8.0 V\tilde V = 8.0\,\mathrm{V} and I~=3.0 eiπ/4 A\tilde I = 3.0\,e^{i\pi/4}\,\mathrm{A}. Someone argues: "the instantaneous power is p(t)=V(t)I(t)p(t)=V(t)I(t), and since V(t)=Re[V~e−iωt]V(t)=\mathrm{Re}[\tilde V e^{-i\omega t}] and I(t)=Re[I~e−iωt]I(t)=\mathrm{Re}[\tilde I e^{-i\omega t}], it follows that p(t)=Re[V~I~ e−2iωt]p(t)=\mathrm{Re}[\tilde V\tilde I\,e^{-2i\omega t}]; averaged over a cycle this is zero because e−2iωte^{-2i\omega t} has zero mean, so the mean power delivered to this load is 0 W0\,\mathrm{W}." ((a)) Explain the error in this reasoning. ((b)) Compute the correct mean power delivered to the load over one cycle.

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