A loudspeaker cone and its flexible suspension can be modelled as a rigid mass on a…

PHYSICS · Multi-part · Fermi University Physics · Oscillations, Waves & Acoustics · Electricity, Magnetism & Electromagnetism · Simple, damped and driven oscillations

Mathematical Methods for Physics, Ch Second-order linear equations: damping, driving and resonance

Problem

A loudspeaker cone and its flexible suspension can be modelled as a rigid mass on a linear spring with a linear damper: the moving mass (cone plus coil) is m=12 gm = 12\,\mathrm{g}, the suspension behaves as a spring of stiffness k=4200 N m−1k = 4200\,\mathrm{N\,m^{-1}}, and mechanical losses in the suspension act as a damper with coefficient b=0.90 kg s−1b = 0.90\,\mathrm{kg\,s^{-1}}, so that mx¨+bx˙+kx=F(t)m\ddot{x} + b\dot{x} + kx = F(t) for the cone's displacement xx from equilibrium, F(t)F(t) being the force from the voice coil. ((a)) Write this equation in the standard form x¨+γx˙+ω02x=F(t)/m\ddot{x} + \gamma\dot{x} + \omega_0^2x = F(t)/m and state ω0\omega_0 and γ\gamma. ((b)) An electrical LCR circuit obeys Lcq¨+Rq˙+q/C=V(t)L_{\mathrm{c}}\ddot{q} + R\dot{q} + q/C = V(t). A designer wants a circuit with the same ω0\omega_0 and γ\gamma as the cone and chooses the inductor to be Lc=2.0 mHL_{\mathrm{c}} = 2.0\,\mathrm{mH}. Find the values of RR and CC this requires.

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