A periodic square-wave voltage of amplitude and period takes the value for and for in…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Fourier analysis and integral transforms · Fourier analysis and integral transforms

Mathematical Methods for Physics, Ch Delta functions, distributions and generalised functions

Problem

A periodic square-wave voltage V(t)V(t) of amplitude A=3.0 VA = 3.0\,\mathrm{V} and period L=4.0×10−3 sL = 4.0\times10^{-3}\,\mathrm{s} takes the value +A+A for 0<t<L/20 < t < L/2 and −A-A for −L/2<t<0-L/2 < t < 0 in each period. Written with Chapter 18's time components, V(t)=∑ncn e−i2πnt/LV(t)=\sum_n c_n\,e^{-i2\pi nt/L}, its complex coefficients are cn=2iA/(πn)c_n = 2iA/(\pi n) for odd nn and cn=0c_n = 0 for even nn. A periodic function's Fourier transform is the spike train V~(ω)=2π∑ncn δ(ω−2πn/L).\tilde V(\omega) = 2\pi\sum_n c_n\,\delta(\omega - 2\pi n/L). ((a)) Give the angular frequency ω1\omega_1 at which the n=1n=1 spike sits, and the magnitude of its weight ∣2πc1∣|2\pi c_1|. ((b)) Do the same for the n=3n=3 spike.

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