A stretched string of length lies along the -axis

PHYSICS · Subjective · Fermi University Physics · Mathematical Methods for Physics · Oscillations, Waves & Acoustics · Superposition, boundaries and interference

Mathematical Methods for Physics, Ch Separation of variables in Cartesian, cylindrical and spherical geometry

Problem

A stretched string of length LL lies along the xx-axis. It is clamped at x=0x=0, so y(0,t)=0y(0,t)=0 for all tt, and its other end at x=Lx=L is attached to a light ring that slides without friction on a smooth vertical rail, so the string exerts no transverse restoring force there: ∂y/∂x=0\partial y/\partial x = 0 at x=Lx=L for all tt. Its transverse displacement y(x,t)y(x,t) obeys the wave equation ∂2y/∂t2=c2 ∂2y/∂x2\partial^2y/\partial t^2 = c^2\,\partial^2y/\partial x^2 with wave speed cc. (a) Substitute y(x,t)=X(x)G(t)y(x,t)=X(x)G(t), separate the wave equation into two ordinary equations joined by a separation constant λ\lambda, and give the argument for why a function of xx alone that equals a function of tt alone for every xx and tt must be a constant. (b) Apply the two boundary conditions to each sign of λ\lambda in turn, and show that only λn=((2n−1)π2L)2\lambda_n=\left(\dfrac{(2n-1)\pi}{2L}\right)^2, n=1,2,3,…n=1,2,3,\dots, gives a standing wave that is not identically zero, with Xn(x)=sin⁡ ⁣((2n−1)πx2L)X_n(x)=\sin\!\left(\dfrac{(2n-1)\pi x}{2L}\right). (c) The string has L=1.2 mL=1.2\,\mathrm{m} and c=180 m s−1c=180\,\mathrm{m\,s^{-1}}. Give the frequencies, in Hz\mathrm{Hz}, of the three lowest modes.

Browse the problem library