A digital length indicator (a comparator gauge) is calibrated against two certified…

PHYSICS · Multi-part · Fermi University Physics · Scientific Practice & Experimental Methods · Quantities, units and the practice of measurement · Uncertainty in measurement

Measurement and Method, Ch The instrument: resolution, sensitivity, calibration and traceability

Problem

A digital length indicator (a comparator gauge) is calibrated against two certified gauge blocks, whose lengths are known to far better precision than the indicator and are treated as exact. Against a 5.000 mm5.000\,\mathrm{mm} block the indicator reads I1=5.008 mmI_1 = 5.008\,\mathrm{mm}. Against a 20.000 mm20.000\,\mathrm{mm} block the indicator reads I2=20.031 mmI_2 = 20.031\,\mathrm{mm}. By repeating a reading several times, the indicator's repeatability is found to be ±0.002 mm\pm0.002\,\mathrm{mm}, and this applies to every reading it gives, including the two calibration readings above. The indicator is then used to measure a component and displays 12.500 mm12.500\,\mathrm{mm}. ((a)) Fit the straight line True =a+b×=a+b\times Indicated through the two calibration points, and use it to find the corrected length corresponding to the displayed 12.500 mm12.500\,\mathrm{mm}. ((b)) Suppose both calibration readings had happened to be biased together, in the same direction, by the full ±0.002 mm\pm0.002\,\mathrm{mm} repeatability (the worst case, since raising either one lowers the corrected length), and recompute the correction to see how much it would shift. Add the component reading's own ±0.002 mm\pm0.002\,\mathrm{mm} repeatability directly to this shift (no quadrature) to obtain a bound on the corrected length.

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