A steel sphere's diameter has four rows in its uncertainty budget: Type A

PHYSICS · Multi-part · Fermi University Physics · Scientific Practice & Experimental Methods · Uncertainty in measurement · Uncertainty in measurement

Measurement and Method, Ch Type A, Type B and the uncertainty budget

Problem

A steel sphere's diameter dd has four rows in its uncertainty budget: Type A, repeated micrometer readings (N=8N=8, s=0.06 mms=0.06\,\mathrm{mm}): u=0.0212 mmu = 0.0212\,\mathrm{mm}. Type A, comparison against a reference sphere over 2020 paired measurements (a correction with best estimate zero): u=0.010 mmu = 0.010\,\mathrm{mm}. Type B, the micrometer's 0.01 mm0.01\,\mathrm{mm} display resolution: u=0.00289 mmu = 0.00289\,\mathrm{mm}. Type B, the micrometer's calibration certificate, ±0.03 mm\pm0.03\,\mathrm{mm} at k=2k=2: u=0.015 mmu = 0.015\,\mathrm{mm}. Someone argues: "Two of these rows are Type A (random error) and two are Type B (systematic error), so they cannot be mixed. First combine within each type: uA=0.02122+0.0102=0.0236 mmu_{\rm A}=\sqrt{0.0212^2+0.010^2}=0.0236\,\mathrm{mm} and uB=0.002892+0.0152=0.0153 mmu_{\rm B}=\sqrt{0.00289^2+0.015^2}=0.0153\,\mathrm{mm}. The total uncertainty is then the sum of the two totals, uA+uB=0.0389 mmu_{\rm A}+u_{\rm B}=0.0389\,\mathrm{mm}, since random and systematic effects are different kinds of thing." ((a)) Identify the error or errors in this reasoning. ((b)) Compute the correct combined standard uncertainty uc(d)u_{\rm c}(d).

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