A WR-90 waveguide has inner width and carries its lowest mode at

PHYSICS · Multi-part · Fermi University Physics · Oscillations, Waves & Acoustics · Electricity, Magnetism & Electromagnetism · Waves in two and three dimensions, dispersion and wave packets

Modes, Packets and Media, Ch Transmission lines and electromagnetic waves in matter, plasmas and guides

Problem

A WR-90 waveguide has inner width a=22.86 mma = 22.86\,\mathrm{mm} and carries its lowest mode at f=10.0 GHzf = 10.0\,\mathrm{GHz}. Someone argues: "The cutoff frequency is fc=c/2a=6.56 GHzf_{\rm c} = c/2a = 6.56\,\mathrm{GHz}. The wave inside the guide is two plane waves crossing at an angle θ\theta to the axis, with cos⁡θ=1−(fc/f)2=0.755\cos\theta = \sqrt{1 - (f_{\rm c}/f)^2} = 0.755. The phase velocity is vp=c/cos⁡θ=1.325c=3.97×108 m s−1v_{\rm p} = c/\cos\theta = 1.325c = 3.97\times10^{8}\,\mathrm{m\,s^{-1}}. Since this is the speed at which the wave travels down the guide, a pulse crossing L=3.00 mL = 3.00\,\mathrm{m} of this guide takes t=L/vp=3.00/(3.97×108)=7.56 nst = L/v_{\rm p} = 3.00/(3.97\times10^{8}) = 7.56\,\mathrm{ns}." ((a)) Identify the error in this reasoning. ((b)) Give the correct transit time for the pulse over 3.00 m3.00\,\mathrm{m} of guide at 10.0 GHz10.0\,\mathrm{GHz}.

Browse the problem library