The chapter's soap film

PHYSICS · Multi-part · Fermi University Physics · Optics & Photonics · Wave propagation and light in media · Wave propagation and light in media

Optics and Photonics, Ch Reflection and transmission at interfaces

Problem

The chapter's soap film, index 1.33 in air and far thinner than a wavelength, reflects nothing because its front and back reflections are equal and opposite. Now put a film of oil (n=1.45n=1.45), again far thinner than a wavelength, on two different surfaces, at normal incidence throughout. As in the chapter, carry the back reflection by the factor t12t21=1−r122t_{12}t_{21}=1-r_{12}^2 for the trip into and out of the film, and ignore anything reflected more than once inside it. ((a)) For the oil film floating on water (n=1.33n=1.33), find the coefficient r12r_{12} of the front reflection and r23r_{23} of the back reflection, each with its sign under CV5, saying for each whether the reflection is external or internal. Add the front arrow to the back arrow carried by t12t21t_{12}t_{21}, and compare the sum with the coefficient of bare water in air. ((b)) Repeat for the same oil film lying on crown glass (n=1.50n=1.50), comparing with bare glass in air. ((c)) Neither film looks black. Say in one sentence what a film far thinner than a wavelength does to the reflection from a surface, and why the soap film in air is the one case that cancels.

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