In a bubble chamber a neutral particle made at a production vertex leaves no track of…

PHYSICS · Multi-part · Fermi University Physics · Particle Physics & Quantum Fields · Particles, interactions and experiment · Particles, interactions and experiment

Particle Physics, Ch The particle zoo and the four interactions

Problem

In a bubble chamber a neutral particle made at a production vertex leaves no track of its own. Some distance downstream, two tracks of opposite charge start from a single point, a V. One is identified as a proton with momentum 900 MeV/c900\,\mathrm{MeV}/c, the other as a π−\pi^- with momentum 250 MeV/c250\,\mathrm{MeV}/c, and the angle between the two tracks at the V is 27.4∘27.4^\circ. Nothing else leaves the V. Many such events, all with the neutral particle at the same momentum, give a mean distance of 7.98 cm7.98\,\mathrm{cm} between the production vertex and the V. Take mp=938.272 MeV/c2m_p = 938.272\,\mathrm{MeV}/c^2 and mπ=139.570 MeV/c2m_\pi = 139.570\,\mathrm{MeV}/c^2. ((a)) Find the mass of the neutral particle. ((b)) Find its momentum, and hence its mean lifetime τ\tau in its own rest frame. ((c)) Use the charges and baryon numbers of the two decay products to decide whether the neutral particle is a meson or a baryon, and identify it from these candidates: neutral kaon (497.6 MeV/c2497.6\,\mathrm{MeV}/c^2), neutron (939.6 MeV/c2939.6\,\mathrm{MeV}/c^2), Λ\Lambda (1115.7 MeV/c21115.7\,\mathrm{MeV}/c^2). Name the interaction that ends its life. ((d)) A neutral kaon decaying to π+π−\pi^+\pi^- lives 8.95×10−11 s8.95\times10^{-11}\,\mathrm{s}. Explain why the lifetime found in (b) could not by itself have told you which particle made the V.

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