In the edge of a fusion device the electrons and ions of a hydrogen plasma are not in…

PHYSICS · Multi-part · Fermi University Physics · Plasma Physics · The plasma state and single-particle motion · The plasma state and single-particle motion

Plasma Physics, Ch What makes an ionised gas a plasma: shielding, the plasma parameter and the natural frequencies

Problem

In the edge of a fusion device the electrons and ions of a hydrogen plasma are not in thermal equilibrium with each other: ne=ni=n=1.0×1019 m−3n_e = n_i = n = 1.0\times10^{19}\,\mathrm{m^{-3}}, Te=20 eVT_e = 20\,\mathrm{eV} and Ti=100 eVT_i = 100\,\mathrm{eV}, with the ions singly charged (Z=1Z=1). Assume the shielding cloud is quasistatic: each species has had time to settle into a Boltzmann density at its own stated temperature around the test charge, while collisions between the species have not yet brought the two temperatures together. Assume also that eϕ≪Te,Tie\phi \ll T_e, T_i everywhere the linearisation is used. ((a)) Starting from Poisson's equation for a test charge with a linearised Boltzmann density for each species, electrons responding through exp⁡(eϕ/Te)\exp(e\phi/T_e) and ions through exp⁡(−eϕ/Ti)\exp(-e\phi/T_i), show that the combined shielding length obeys 1λD2=1λDe2+1λDi2,λDs=(ϵ0Tsnse2)1/2,\frac{1}{\lambda_D^2} = \frac{1}{\lambda_{De}^2} + \frac{1}{\lambda_{Di}^2}, \qquad \lambda_{Ds} = \left(\frac{\epsilon_0T_s}{n_se^2}\right)^{1/2}, where λDs\lambda_{Ds} is the Debye length that species ss alone would give. ((b)) Evaluate λDe\lambda_{De}, λDi\lambda_{Di} and the combined λD\lambda_D for the stated plasma, and say which species dominates the shielding.

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