A coronal loop carries a magnetic field of magnitude

PHYSICS · Multi-part · Fermi University Physics · Astrophysics & Cosmology · Plasma Physics · Fluid and magnetohydrodynamic description

Plasma Physics, Ch Magnetohydrodynamics: Ohm's law for a moving plasma, frozen flux and magnetic pressure

Problem

A coronal loop carries a magnetic field of magnitude B=0.020 TB = 0.020\,\mathrm{T}, taken uniform in magnitude both along the loop and across it over the region considered, whose field lines are curved with radius of curvature Rc=3.0×107 mR_c = 3.0\times10^{7}\,\mathrm{m}. The loop plasma is hydrogen (mi=mpm_i = m_p) with ni=ne=1.0×1015 m−3n_i = n_e = 1.0\times10^{15}\,\mathrm{m^{-3}} and Ti=Te=100 eVT_i = T_e = 100\,\mathrm{eV}, and its resistivity is η=9.0×10−7 Ω m\eta = 9.0\times10^{-7}\,\Omega\,\mathrm{m}. Take the loop length scale for the Alfven time and Lundquist number to be L=RcL = R_c. ((a)) Using the ion Larmor radius rLi=miv⊥i/eBr_{Li} = m_iv_{\perp i}/eB with v⊥i=(2Ti/mi)1/2v_{\perp i} = (2T_i/m_i)^{1/2}, check that rLi≪Rcr_{Li} \ll R_c, so that treating the field as a smooth curved line (rather than resolving individual gyro-orbits) is justified. ((b)) Because BB is uniform in magnitude along and across the loop, ∇⊥(B2/2μ0)=0\nabla_\perp(B^2/2\mu_0) = 0, so the perpendicular-gradient (pressure) part of j×B\mathbf{j}\times\mathbf{B} vanishes and the force is pure tension, B2κ/μ0B^2\boldsymbol{\kappa}/\mu_0 with ∣κ∣=1/Rc|\boldsymbol{\kappa}| = 1/R_c. Find its magnitude, and also find the ratio of plasma to magnetic pressure, β=n(Ti+Te)/(B2/2μ0)\beta = n(T_i+T_e)/(B^2/2\mu_0), treating p=niTi+neTep = n_i T_i + n_e T_e as the sum of the two fluid pressures. ((c)) Find the Alfven speed vAv_A, the Alfven time τA=L/vA\tau_A = L/v_A, and the Lundquist number S=μ0LvA/ηS = \mu_0 L v_A/\eta.

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