Bob receives a two-qubit state guaranteed to be one of the four Bell states on qubits…

PHYSICS · Multi-part · Fermi University Physics · Quantum Information & Technology · Quantum states, measurement and entanglement · The quantum circuit model and quantum algorithms

Quantum Information and Technology, Ch The quantum circuit model

Problem

Bob receives a two-qubit state guaranteed to be one of the four Bell states ∣βjk⟩=(ZjXk⊗I)∣Φ+⟩|\beta_{jk}\rangle = (Z^jX^k\otimes I)|\Phi^+\rangle on qubits 1 and 2, with ∣Φ+⟩=12(∣00⟩+∣11⟩)|\Phi^+\rangle = \frac{1}{\sqrt2}(|00\rangle + |11\rangle) (Chapter 4's Bell-state notation). He wants to learn kk without doing a full Bell measurement, which would also reveal, and disturb, jj. He introduces an ancilla qubit 3, prepared in ∣+⟩|+\rangle (Chapter 1), and applies the two-qubit gate C(Z)C(Z) with qubit 3 as control and qubit 1 as target, immediately followed by C(Z)C(Z) with qubit 3 as control and qubit 2 as target. He then measures qubit 3 in the XX basis, that is he applies HH to qubit 3 and measures in the computational basis. ((a)) Write the 4×44\times4 matrix of C(Z)C(Z), control first and target second, in the computational basis ∣00⟩,∣01⟩,∣10⟩,∣11⟩|00\rangle,|01\rangle,|10\rangle,|11\rangle, and check it is unchanged if the roles of control and target are swapped. ((b)) The state ∣βjk⟩|\beta_{jk}\rangle is an eigenstate of Z1Z2Z_1Z_2 with eigenvalue (−1)k(-1)^k, since Z1X1=−X1Z1Z_1X_1 = -X_1Z_1 and Z1Z2∣Φ+⟩=∣Φ+⟩Z_1Z_2|\Phi^+\rangle = |\Phi^+\rangle. Show that the two controlled-ZZ gates together act on the ancilla and the Bell pair as a controlled version of the joint operator Z1Z2Z_1Z_2, derive by phase kickback the resulting state of qubit 3, and hence show that measuring qubit 3 in the XX basis reveals kk with certainty while leaving qubits 1 and 2 in the state ∣βjk⟩|\beta_{jk}\rangle, undisturbed. ((c)) Bob now wants to apply an XX gate to qubit 1, conditioned on the qubit-3 outcome, so as to convert the pair to one with k=0k=0. Use the deferred measurement principle to redraw the protocol so that qubit 3 is measured only at the very end of the whole circuit, and state why the final joint statistics of qubits 1 and 2 are unchanged by this reordering.

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