A source emits symbols independently with ,

PHYSICS · Multi-part · Fermi University Physics · Quantum Information & Technology · Quantum information theory and communication · Quantum information theory and communication

Quantum Information and Technology, Ch Entropy and compression

Problem

A source emits symbols independently with P(1)=0.3P(1)=0.3, P(0)=0.7P(0)=0.7, giving binary entropy H=h(0.3)=0.881H=h(0.3)=0.881 bits per symbol. Someone argues: 'I can compress this source at rate R=0.7R=0.7 bits per symbol, below HH, and still keep the error small. For a block of nn symbols I encode only the 2nR2^{nR} most probable sequences and declare a failure on the rest. Because the source is not perfectly random, its probability is concentrated on a small set of highly likely sequences, so as nn grows the fraction of blocks that fall outside my encoded set keeps shrinking. A fixed rate below HH with a small, stable error is therefore possible.' ((a)) Identify the error in this reasoning, referring to the size and probability of the typical set. ((b)) For a block of n=2000n=2000 symbols and ϵ=0.05\epsilon=0.05 bits, use Chebyshev's inequality to bound the probability δ\delta that a block is atypical, and use the size of the typical set to bound the fraction of its probability that 2nR2^{nR} sequences can cover. Hence bound the probability that the scheme above succeeds, and say what happens to that bound as n→∞n\to\infty.

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