The two Josephson relations are and

PHYSICS · Multi-part · Fermi University Physics · Condensed Matter, Materials & Soft Matter · Quantum Information & Technology · Physical realizations and quantum technologies

Quantum Information and Technology, Ch Superconducting qubits and circuit QED

Problem

The two Josephson relations are I=Icsin⁡φI = I_c\sin\varphi and V=ℏ2edφdtV = \dfrac{\hbar}{2e}\dfrac{d\varphi}{dt}, with φ\varphi the gauge-invariant phase difference across the junction and IcI_c its critical current. ((a)) Using V=LJ dI/dtV = L_J\,dI/dt for an inductor, derive the phase-dependent Josephson inductance LJ(φ)L_J(\varphi). ((b)) Using dE/dt=IVdE/dt = IV, derive the junction's potential energy −EJcos⁡φ-E_J\cos\varphi (up to an additive constant) and identify EJE_J in terms of IcI_c. ((c)) A symmetric split junction (two identical junctions of critical current Ic0I_{c0}, joined into a loop threaded by an external flux Φ\Phi, so that the pair behaves as one effective junction of critical current Ic(Φ)=Ic∣cos⁡(πΦ/Φ0)∣I_c(\Phi) = I_c|\cos(\pi\Phi/\Phi_0)|, with Ic=2Ic0=30.0 nAI_c = 2I_{c0} = 30.0\,\mathrm{nA} its value at zero flux and Φ0=h/2e\Phi_0 = h/2e the flux quantum) is biased at Φ=Φ0/3\Phi = \Phi_0/3. Using ℏ=1.0546×10−34 J s\hbar = 1.0546\times10^{-34}\,\mathrm{J\,s}, h=6.6261×10−34 J sh = 6.6261\times10^{-34}\,\mathrm{J\,s} and e=1.6022×10−19 Ce = 1.6022\times10^{-19}\,\mathrm{C}, find the effective critical current at Φ=Φ0/3\Phi = \Phi_0/3, and hence EJ/hE_J/h and LJ(0)L_J(0) there (still ℏ/2eIc(Φ)\hbar/2eI_c(\Phi), the linear inductance of the effective junction at zero phase). Then, for a transmon built on this split junction with EC/h=0.250 GHzE_C/h = 0.250\,\mathrm{GHz} fixed and f01≈8EJEC/h−EC/hf_{01} \approx \sqrt{8E_JE_C}/h - E_C/h, find f01f_{01} at zero flux and at Φ=Φ0/3\Phi = \Phi_0/3.

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