Phase estimation's controlled-power ladder reads a phase to bits of precision using…

PHYSICS · Multi-part · Fermi University Physics · Quantum Information & Technology · The quantum circuit model and quantum algorithms · Physical realizations and quantum technologies

Quantum Information and Technology, Ch Quantum metrology and sensing

Problem

Phase estimation's controlled-power ladder reads a phase φ\varphi to tt bits of precision using tt control qubits, the jjth of which controls U2jU^{2^j} on the target register, for j=0,1,…,t−1j=0,1,\ldots,t-1; this ladder is the engine inside both order finding (used by Shor's algorithm) and quantum counting (used inside amplitude estimation). Resolving the same tt-bit phase ambiguity with GHZ states, as in a GHZ magnetometer, uses a ladder of GHZ states of sizes 20,21,…,2t−12^0,2^1,\ldots,2^{t-1}, the state of size 2j2^j giving a parity fringe cos⁡(2jφ)\cos(2^j\varphi) read out by a chain of CNOTs, one Hadamard and one measurement, mirroring the powers of UU. ((a)) For t=6t=6 bits of precision, state the number of controlled-power gates in the phase-estimation ladder, and the total number of applications of UU they contain if each controlled-U2jU^{2^j} is built by applying controlled-UU 2j2^j times. ((b)) For the same t=6t=6 bits, state the total number of atoms consumed if the GHZ ladder uses one fresh copy of each sized state, used once. ((c)) For the same t=6t=6 bits, state the size of the largest GHZ state the ladder needs, and the power of UU it mirrors. ((d)) Using the result that under independent dephasing no entangled state of NN atoms beats independent atoms by more than a factor e\sqrt e, explain in two or three sentences why adding rungs to the GHZ ladder stops improving precision, whereas adding control qubits to an ideal phase-estimation ladder does not, although both ladders spend the same total evolution.

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