A nucleus confines its protons and neutrons to a region of size fm ( fm m)

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Origins of quantum theory · Origins of quantum theory

Quantum Mechanics: From the Photon to the Hydrogen Atom, Ch Matter waves and wave-particle duality

Problem

A nucleus confines its protons and neutrons to a region of size Δx=4.4\Delta x = 4.4 fm (11 fm =10−15= 10^{-15} m). Use the estimating form of the uncertainty relation, Δp∼ℏ/Δx\Delta p \sim \hbar/\Delta x, with ℏ=1.055×10−34\hbar = 1.055\times10^{-34} J s, mp=1.673×10−27m_p = 1.673\times10^{-27} kg, me=9.109×10−31m_e = 9.109\times10^{-31} kg, c=3.00×108c = 3.00\times10^{8} m s−1^{-1}, mec2=0.511m_ec^2 = 0.511 MeV and 11 eV =1.602×10−19= 1.602\times10^{-19} J. ((a)) Estimate the least kinetic energy of a proton confined to this region, in MeV, treating it non-relativistically. ((b)) Repeat the estimate of Δp\Delta p for an electron confined to the same region, and use it in the non-relativistic formula K=(Δp)2/2meK = (\Delta p)^2/2m_e, again in MeV. Compare the result with the electron's own rest energy mec2m_ec^2, and explain why this formula cannot be trusted here. ((c)) Chapter 1 gives the electron's relativistic energy as E=p2c2+me2c4E = \sqrt{p^2c^2+m_e^2c^4}, which reduces to E≈pcE \approx pc when pc≫mec2pc \gg m_ec^2. Using the same Δp\Delta p as in (b), estimate the electron's kinetic energy in this extreme-relativistic limit, in MeV. ((d)) Beta decay ejects electrons from nuclei of this size with observed energies typically of a few MeV. Compare this with your answer to (c), and state in one sentence what the comparison suggests about whether an electron could exist, ready-formed, inside the nucleus before the decay.

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