A laboratory wants to look at detail on the scale of the atomic spacing

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Condensed Matter, Materials & Soft Matter · Origins of quantum theory

Quantum Mechanics: From the Photon to the Hydrogen Atom, Ch Matter waves and wave-particle duality

Problem

A laboratory wants to look at detail on the scale of the atomic spacing, about 0.200.20 nm. Its light microscope uses green light of wavelength 550550 nm; its electron instrument accelerates electrons through 1010 kV, giving them a kinetic energy of 1010 keV. Treat the electrons non-relativistically and use λ=1.226 nm/K/eV\lambda = 1.226\ \mathrm{nm}/\sqrt{K/\mathrm{eV}}. As a working rule, an instrument using waves of wavelength λ\lambda can just resolve detail of size λ/2\lambda/2. ((a)) Find the de Broglie wavelength of a 1010 keV electron, in nm. ((b)) By what factor is it smaller than the wavelength of the green light? ((c)) State the finest detail each instrument can resolve, in nm, and say which of them can see the 0.200.20 nm atomic spacing. ((d)) The same electrons are sent through a thin crystal whose atomic rows are D=0.215D = 0.215 nm apart. Using Dsin⁡θ=λD\sin\theta = \lambda for the first-order peak, find the angle of that peak, in degrees, and say in one sentence what this implies about the length of the instrument's camera.

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