A neutron ( kg) wave packet has kinetic energy MeV

PHYSICS · Subjective · Fermi University Physics · Oscillations, Waves & Acoustics · Quantum Mechanics · Wave mechanics in one dimension

Quantum Mechanics: From the Photon to the Hydrogen Atom, Ch Free particles, wave packets and tunnelling

Problem

A neutron (mn=1.6749×10−27m_n = 1.6749\times10^{-27} kg) wave packet has kinetic energy 5.05.0 MeV. One argument runs: "the packet is a wave with wavenumber k0k_0 and angular frequency ω0=ℏk02/2mn\omega_0 = \hbar k_0^2/2m_n, so the particle travels at the wave's speed ω0/k0\omega_0/k_0," giving ω0/k0=1.55×107 m s−1\omega_0/k_0 = 1.55\times10^7\ \mathrm{m\,s^{-1}}.Is this the neutron's actual speed? If not, say what it is instead, find the correct value, and say what physical thing ω0/k0\omega_0/k_0 does describe.

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