A student offers this argument that is Hermitian: "

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

Quantum Mechanics: From the Photon to the Hydrogen Atom, Ch Observables, commutators and the uncertainty relations

Problem

A student offers this argument that Q^=d/dx\hat Q = d/dx is Hermitian: "∫f∗(Q^g) dx=∫f∗g′ dx\int f^*(\hat Qg)\,dx = \int f^*g'\,dx. Integrating by parts, =[f∗g]−∞∞−∫(f∗)′g dx= \big[f^*g\big]_{-\infty}^{\infty} - \int(f^*)'g\,dx. The boundary term vanishes for normalisable functions, and (f∗)′=(f′)∗(f^*)' = (f')^*, so ∫f∗(Q^g) dx=−∫(f′)∗g dx=−∫(Q^f)∗g dx\int f^*(\hat Qg)\,dx = -\int(f')^*g\,dx = -\int(\hat Qf)^*g\,dx. Since this differs from +∫(Q^f)∗g dx+\int(\hat Qf)^*g\,dx only by a minus sign, and a minus sign is just a convention, Q^\hat Q is Hermitian." Find the error in this argument.

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